[tex] \frac{x+1}{ \sqrt{3} +2} + \sqrt{3} =2-x[/tex]
rationalizam √3-2
(x+1)(√3-2)+√3=2-x
√3x-2x+√3-2+√3=2-x
x(√3-2+1)=4-2√3
x=[tex] \frac{4-2 \sqrt{3} }{ \sqrt{3}-1 } = \frac{(4-2 \sqrt{3) ( \sqrt{3}+1) } }{2} = \frac{4 \sqrt{3}+4-2*3-2 \sqrt{3} }{2} = \frac{2 \sqrt{3}-2 }{2} = \sqrt{3} -1[/tex]
