aducem la acelasi numitor in paranteza; numitorul va fi 30
[tex] (\frac{-12}{30} + \frac{15}{30}- \frac{10}{30} )* \frac{15}{7} )^3+ \frac{1}{8} [/tex]
[tex]( \frac{-7}{30} * \frac{15}{7} )^3+ \frac{1}{8} =( \frac{-1}{3} )^3+ \frac{1}{8} = \frac{-1}{8} + \frac{1}{8} =0[/tex]
