[tex](^{\sqrt{2})} \frac{ \sqrt{2} }{ \sqrt{3} } +^{\sqrt{3})} \frac{ \sqrt{3} }{ \sqrt{2} } + \frac{1}{ \sqrt{6} } ): \sqrt{6}=\\
=( \frac{2}{ \sqrt{6} }+\frac{3}{ \sqrt{6} }+\frac{1}{ \sqrt{6} }):\sqrt{6}=\\
= \frac{6}{ \sqrt{6} } \cdot \frac{1}{ \sqrt{6} }=1[/tex]
