Calculeaza concentratia de ioni hidroniu dintr-o solutie ce prezinta urmatoarele valori ale ph-ului:a) 11,013b) 4,902c)7,002d) 6,127e)13,191f) 12,77

Răspuns :

plecam de la formula:   pH= - log[H3O+]
a) 11,013= -log[H3O+] => [H3O+] = [tex] 10^{-11,013} [/tex]
b) 4,902= - log[H3O+] => [H3O+]= [tex] 10^{-4,902} [/tex]
c) 7,002= - log[H3O+] => [H3O+]= [tex] 10^{-7,002} [/tex]
d)  6,127= - log [H3O+] => [H3O+]= 10^{-6,127} [/tex]
e) 13,19= -log[H3O+] => [H3O+]= [tex] 10^{-13,19} [/tex]
f) 12,77= -log[H3O+] => [H3O+]= [tex] 10^{-12,77} [/tex] 

sunt niste numere cam ciudate,dar asta e algoritmul corect