Răspuns :
ΔABC, mas<A=90
AD _|_ BC
AD-h
AD=AB*AC/BC= 4*10/12= 10/3
AB²=BD*BC
4²=BD*12
16=BD*12
BD=16/12= 4/3
AC²=DC*BC
10²=DC*12
100=DC*12
DC=100/12= 25/3
AD _|_ BC
AD-h
AD=AB*AC/BC= 4*10/12= 10/3
AB²=BD*BC
4²=BD*12
16=BD*12
BD=16/12= 4/3
AC²=DC*BC
10²=DC*12
100=DC*12
DC=100/12= 25/3
ΔABC dreptunghic in A
BC = 12cm
AC=10cm
AB=4cm.
AD_|_ BC, D ∈ BC.
AC²= DC·BC
10²=12DC
DC= 100/12 => DC = 25/3 cm.
AB²= 12BD
16=12BD
BD= 16/12
BD=4/3cm
BC = 12cm
AC=10cm
AB=4cm.
AD_|_ BC, D ∈ BC.
AC²= DC·BC
10²=12DC
DC= 100/12 => DC = 25/3 cm.
AB²= 12BD
16=12BD
BD= 16/12
BD=4/3cm