1) lungimea sarmei=Px5
P=2(l+L)=2(12+6)=36 m
2)distanta cea mai mare=diagonala=AC
in ΔABC-dreptunghic=> AC²=BC²+AB²=12²+6²=144+36=180
AC=√180=6√5 m
3) aria ramasa=aria gradina-aria patrat=72-1=71m²
aria gradina=l×L=72m²
aria patrat=1m²
AMPD-trapez dreptunghic=> aria AMPD= (AD+MP)×AM÷2=6+1)×11÷2=77÷2m²
aria lui DPNC= aria ramasa-aAMDP=71-77÷2=65÷2m