(√18 + √288) -(√98 + √200)= ? 


Răspuns :

(3√2+12√2)-(7√2+10√2)
15√2-17√2=-2√2
√18  = [tex] \sqrt{9*2} =3* \sqrt{2} [/tex]
√288 = [tex] \sqrt{144 * 2} = 12 \sqrt{2} [/tex]
√98  =[tex] \sqrt{49*2} =7* \sqrt{2} [/tex]
√200 = [tex] \sqrt{100*2} =10 * \sqrt{2} [/tex]
(3* [tex] \sqrt{2} [/tex] + 12 * [tex] \sqrt{2} [/tex] )- (7*  [tex] \sqrt{2 [/tex] + 10 * [tex] \sqrt{2} [/tex])
=[tex]15 \sqrt{2} -17 \sqrt{2} =-2 \sqrt{2} [/tex]