Răspuns :
a) [tex] \frac{1}{6} + \frac{3}{8} = \frac{4+3*3}{24} = \frac{12}{24} = \frac{1}{2} [/tex]
b) [tex] \frac{7}{20} - \frac{1}{10} = \frac{7-2*1}{20} = \frac{5}{20} = \frac{1}{4} [/tex]
c)[tex] \frac{5}{4} * \frac{3}{4} = \frac{5*3}{4*4} = \frac{15}{16} [/tex]
d)[tex] \frac{1}{3} + \frac{1}{3} = \frac{1+1}{3} = \frac{2}{3} [/tex]
e)[tex] \frac{6}{8} : 2 = \frac{6}{8} : \frac{2}{1} = \frac{6}{8} * \frac{1}{2} = \frac{6*1}{8*2} = \frac{6}{16} = \frac{3}{8} [/tex]
f)[tex] \frac{12}{8} + \frac{1}{1} = \frac{12+ 8*1}{8} = \frac{20}{8} = \frac{5}{2} [/tex]
g)[tex] \frac{2}{15} + \frac{1}{35} = \frac{7*2 +3*1 }{105} = \frac{17}{105} [/tex]
h)[tex] \frac{2}{3} : \frac{1}{35} = \frac{2}{3} * \frac{35}{1} = \frac{35*2}{3*1} = \frac{70}{3} [/tex]
b) [tex] \frac{7}{20} - \frac{1}{10} = \frac{7-2*1}{20} = \frac{5}{20} = \frac{1}{4} [/tex]
c)[tex] \frac{5}{4} * \frac{3}{4} = \frac{5*3}{4*4} = \frac{15}{16} [/tex]
d)[tex] \frac{1}{3} + \frac{1}{3} = \frac{1+1}{3} = \frac{2}{3} [/tex]
e)[tex] \frac{6}{8} : 2 = \frac{6}{8} : \frac{2}{1} = \frac{6}{8} * \frac{1}{2} = \frac{6*1}{8*2} = \frac{6}{16} = \frac{3}{8} [/tex]
f)[tex] \frac{12}{8} + \frac{1}{1} = \frac{12+ 8*1}{8} = \frac{20}{8} = \frac{5}{2} [/tex]
g)[tex] \frac{2}{15} + \frac{1}{35} = \frac{7*2 +3*1 }{105} = \frac{17}{105} [/tex]
h)[tex] \frac{2}{3} : \frac{1}{35} = \frac{2}{3} * \frac{35}{1} = \frac{35*2}{3*1} = \frac{70}{3} [/tex]