1,7(3)= 1intreg (73-7)/90= 1 intreg 66/90 = 1 intreg 22/30= 52/30= 26/15
a= 1/3 din b= 1/3 * b= b/3
b= 1/3 din c= 1/3 * c= c/3
a=c/3/3= c/3 * 1/3= c/9
ma=(a+b+c)/3= 26/15
a+b+c= 3*26/15
a+b=c= 26/5
c/9 + c/3 + c= 26/5 aducem la acelasi numitor
5c + 15c +45c= 234
65c= 234
c=3,6
a= 3,6/9= 0,4
b= 3,6/3= 1,2
