Ontrissask
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[tex] \sqrt{18} - \sqrt{50}+ \sqrt{200} = ?[/tex]

Răspuns :

Petrwask
√18-√50-√200
=3√2-5√2-10√2
= -12√2
Antonio9990ask
[tex] \sqrt{18}- \sqrt{50}+ \sqrt{200}= \\ [/tex]
[tex]3 \sqrt{2} -5 \sqrt{2} +10 \sqrt{2} = \\ -2 \sqrt{2} +10 \sqrt{2}=\\ -12 \sqrt{2} [/tex]

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