CH3OH + H2O ---> CO2 + 3 H2
1 mol H2O........6,022 * 10 la 23 molecule
10 moli H2O............x molecule x = 6,022 * 10 la 24 molecule
1 mol CH3OH.........6.022 * 10 la 23 molecule
y moli CH3OH..............6.022 * 10 la 23 molecule y = 10 moli CH3OH
nr moli = masa/masa molara => masa CH3OH = 10*32 = 320 g metanol
Cele doua lichide se pot separa prin distilare.