ABCD-romb
AB=BC=CD=AD=10
AC;BD-diag
BD=12
fie [AM _|_ DB
AM-h
M-mij lui DB <=> DM=MB=BD/2= 12/2= 6
ΔAMB, mas<M=90 =>AM²=AB²-MB²= 10² -6² =100-36=64 =>AM=8
AC intersectat DB ={M} <=> M-mij lui AC
AM=MC=AC/2 =>AC=2AM=2*8=16
A ABCD= d1 *d2 /2= AC*BD/2= 16*12/2= 8*12= 96
