Deboranatiask
a fost răspuns

cine ma ajuta?...
 2√7supra 25+5√700supra3+20√900supra4

Răspuns :

Miky93ask
2v7supra 25 +50v7 supra3 + 60/4 se simplifica 60/4
2v7/25 +50v7 /3 +15  aducem la acelasi numitor(75)
6v7+1250v7 +1125
1256v7+1125
[tex] \frac{2\sqrt7}{25} + \frac{5\sqrt{700}}{3} + \frac{20\sqrt{900}}{4} = \frac{2\sqrt7}{25} + \frac{50\sqrt7}{3} + \frac{20\cdot30}{4} = \frac{6\sqrt7+50\cdot25\sqrt7}{75} +150=[/tex]
[tex]= \frac{1256\sqrt7}{75} +150[/tex]