a fost răspuns

a=9x7-2x4-5x10     b=98-(7x7+3x7+5x3)      c=13+7x4)-39 calculeaza 2a+3c-b=? b+4a-2c=?    (a+c)x  9-b=?

Răspuns :

Petrwask
a=9x7-2x4-5x10
a=63-8-50
a=5

 b=98-(7x7+3x7+5x3)
 b=98-(49+21+15)
 b=98-85
 b=13
  
c=(13+7x4)-39 
c=(13+28)-39
c=41-39
c=2


2a+3c-b=2x5+3x12-13
=10+36-13
=46-13
=34



b+4a-2c=12+4x5-2x2
=12+20-4
=32+4
=28

(a+c)x  9-b=(5x2)x 9-13
=10x (-4)
=-40
a=9×7-2×4-5×10
a=63-8-50
a=55-50
a=5

b=98- ( 7×7+3×7+5×3)
b= 98- ( 49+21+15)
b= 98- (70 +15)
b= 98-85
b=13

c= ( 13+7×4)-39
c= ( 13+ 28) -39
c= 41-39
c=2

2a+3c-b
2×5+3×2-13
10+6-13
16-13
3

b+4a-2c
13+4×5-2×2
13+20-4
33-4
29

( a+c)×9-b
( 5+2)×9-13
7×9-13
63-13
50