Răspuns :
in prima zi parcurge [tex] \frac{a}{2} [/tex]
a doua zi parcurge [tex] \frac{a}{3} [/tex]
a treia zi a-( [tex] \frac{a}{2} + \frac{a}{3} [/tex] )
a doua zi parcurge [tex] \frac{a}{3} [/tex]
a treia zi a-( [tex] \frac{a}{2} + \frac{a}{3} [/tex] )
in prima zi parcurge a/2,
in a doua zi a/3
iar ultima zi parcurge :
a-a/2-a/3=6a/6-3a/6-2a/6= a/6, adica o sesime
in a doua zi a/3
iar ultima zi parcurge :
a-a/2-a/3=6a/6-3a/6-2a/6= a/6, adica o sesime