Georgianageo181ask
a fost răspuns

Descompuneti in factori, grupand mai intai convenabil factorii:

a)6x²+12ax+5xy²+10ay²

b)3a²b²+5abc²-3ab-5c²

c)7[tex] x^{4} [/tex] + 8xy³-7x3y-8 [tex] y^{4} [/tex]

Ajutati-ma, va rog!

Răspuns :

Miky93ask
a)6x(x+2a)+5y²(x+2a)=  (x+2a)(6x+5y²)

b)3a²b²-3ab+5abc²-5c²= 3ab(ab-1)+5c²(ab-1)= (ab-1)(3ab+5c²)

c)7x⁴-7xy³+8xy³-8y⁴= 7x(x³-y³)+8y³(x-y)= (x-y)(x²-y²)(7x+8y³)= (x-y)(x+y)(x-y)(7x+8y³)= 

=(x-y)²(x+y)(7x+8y³)