a fost răspuns

stiind ca a plus b este 32 si b plus c e 45,calculati valorile numerelor
2a plus 5b plus 3c
a plus 5b plus 4c
3a plus 7b plus 4c

Răspuns :

Miky93ask
2a+5b+3c=2(a+b)+3(b+c)= 2a+2b+3b+3c=

=2*32+3*45= 64+135=199

a+5b+4c=a+b+ 4(b+c)= a+b+4b+4c=

=32+4*45= 32+180= 212

3a+7b+4c=3(a+b)+4(b+c)=3a+3b+4b+4c=

=3*32+4*45=96 +180=  276

Ask Alte intrebari