Elaaleask
a fost răspuns

a)Daca 3*x+4*y+5*z+27=59, determinati 5*z+3*x+4*y :

b)Stiind ca x-2*y+13=52 , determinati 3*x-6*y+1: 
HELP:)!

Răspuns :

Miky93ask
a)5z + 3x+4y= 59-27
5z+3x+4y=32

b)x-2y+13=52
x-2y=52-13
x-2y=39

3x-6y+1=  3(x-2y)+1= 3*39+1=  117+1= 118
Gnocchiask
5z+3x+4y=59-27


x-2y=52-13=39
=>3(x-2y)=3x-6y=39*3=117; 3x-6y+1=118