1) a)
6/(3x - 2) ∈ Z
=> 3x-2 este divizor al lui 6 in Z
x₁ = 0 => 6 / (-2) = -3
x₂ = 1 => 6 / 1 = 6
1) b)
-5/(2x - 1) ∈ Z
x₁ = 3 => -5 / 5 = -1
x₂ = 1 => -5 / 1 = -5
x₃ = 0 => -5 / (-1) = 5
x₄ = -2 => -5 / (-5) = 1
1) c)
(2x + 7)/(2x + 3) ∈ Z
x₁ = -1 => 5 / 1 = 5
x₂ = -2 => 3 / (-1) = -3
2)
x - 3x/5 - 24 = 40
2x/5 = 64
2x = 64 * 5
x = (64 * 5)/2 = 32 * 5 = 160 lei a primit de la bunicul.