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Numerele 122,149,176 impartite la acelasi numar natural dau resturile respectiv10,9si 8 .Aflati impartitorul.

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Miky93ask
122:x=c1 rest 10
122=xc1 +10
xc1= 122-10=112

149:x=c2 rest 9
149=xc2 +9
xc2=149-9=140

176:x=c3 rest 8
176=xc3 +8
xc3=176-8=168

x=[112;140;168]

112=2^4  *7
140=2^2 *5*7
168=2^3 * 3*7

x=2^4*3*5*7
x=1680

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