Răspuns :
[tex] 25^{x} < \frac{ 125^{7} }{ 5^{9} } <=> 5^{2x} < \frac{ 5^{21} }{ 5^{9} } <=> 5^{2x} < 5^{12} [/tex]
2x < 12
x < 6
E = {0; 1; 2; 3; 4; 5}
F = {(5-0); (5-1)....(5-5)}
F = {0; 1; 2; 3; 4; 5}
=> E = F
E U F = E = F
E ∩ F = E = F
E / F = Ф
F / E = Ф
2x < 12
x < 6
E = {0; 1; 2; 3; 4; 5}
F = {(5-0); (5-1)....(5-5)}
F = {0; 1; 2; 3; 4; 5}
=> E = F
E U F = E = F
E ∩ F = E = F
E / F = Ф
F / E = Ф
25 ^x = (5²)^x
125⁷=(5³)⁷= 5²¹
5²¹ :5⁹= 5¹⁸
5²x < 5¹⁸
2x < 18 |:2
x < 9
x∈N ⇒x∈{1,2,3,4,5,6,7,8}
E={1,2,3,4,5,6,7,8}
y=5-x
y=5-1=4
y=5-2=3
y=5-3=2
y=5-4=1
y=5-5=0
y=5-6=-1
y=5-7=-2
y=5-8=-3
y∈N* ⇒y∈{1,2,3,4}
a)E u F={1,2,3,4,5,6,7,8}
E intersectat F= {1,2,3,4}
E/F={Ф}
F/E={5,6,7,8}
125⁷=(5³)⁷= 5²¹
5²¹ :5⁹= 5¹⁸
5²x < 5¹⁸
2x < 18 |:2
x < 9
x∈N ⇒x∈{1,2,3,4,5,6,7,8}
E={1,2,3,4,5,6,7,8}
y=5-x
y=5-1=4
y=5-2=3
y=5-3=2
y=5-4=1
y=5-5=0
y=5-6=-1
y=5-7=-2
y=5-8=-3
y∈N* ⇒y∈{1,2,3,4}
a)E u F={1,2,3,4,5,6,7,8}
E intersectat F= {1,2,3,4}
E/F={Ф}
F/E={5,6,7,8}