a)2( x+1/5)=7/4 aducem la acelasi numitor in paranteza
2 (5x+1)/5=7/4
(10x+2)/5=7/4
4(10x+2)=5*7
40x+8=35
40x=35-8
40x=27
x=27/40
b)1,(3)=1 intreg 3/9= 1 intreg 1/3= 4/3
0,75=75/100=3/4
4/3 * (3x-3/4)=1/3 aducem la acelasi numitor in paranteza
4/3 * (12x-3)/4=1/3
(12x-3)/3=1/3
12x-3=1
12x=1+3
12x=4
x=4/12= 1/3
