Puricerazvanask Puricerazvanask Matematică a fost răspuns Salut! (As dorii opinia voastra)x=distanta maximaI) 20/100din x =)R1II)30/100 din R1=)R2III)R2=560km------------------------------------x=?------------------------------------Distanta parcursa in ultimele 2 zile?x=R1- 30/100dinR1=R2 =) 70/100dinR1=560=)X=560:7/10=)X=800KmDistanta parcursa in ultimele 3 zile?x-20/100din X=800 =)4/5din x=800 =)x=800:4/5 =)x=1000km Raspuns:Distanta parcuras in ultimele 3 zile este de 1000km