a= 2/ 3+√7 rationalizam
a= (6-2√7)/ (9-7)=
a= (6-2√7)/2
b=3+√2 - √3 intregi 1/2=
b=3+√2 -√7/2 aducem la acelasi numitor
b=(6+2√2-√7)/2
mg=√ab
mg=√( 6-2√7)/2 * (6+2√2-√7)/2
mg=√ (36+12√2-6√7-12√7-4√14 +14)/4
mg=√ (50+12√2-18√7-4√14)/4
mg= √(50+12√2-18√7-4√14)/2
