a fost răspuns

Determinati numerele intregi negative, mai mari decat (-3), care verifica inegalitatiile:
a) 3x-2[tex] \geq [/tex]5x-8;
b) 3x-9[tex] \leq [/tex]5x-1
c) -x(7-5)-5[tex] \geq [/tex]2x-1;
este urgent!!

Răspuns :

8-2≥5x-3x
4≥2x|:2
2≥x
x apartine{de la - infinit...2}

1-9≤5x-3x
-8≤2x|:2
-4≤x{-4,-3,-2,-1,0...+infinit}

-7x+5x-5≥2x-1
-2x-2x≥5-1
-4x≥4| ·-1
4x≤-4|:4
x≤-1
{-infinit....-1}
x