Răspuns :
3x²-7x+6 < 2 (x²+x-1)
3x²-2x²-7x-2x+6+2<0
x²-9x+8<0
Δ=81-4*1*8=81-32=49
Δ=+7,-7
x1,2=-b+√Δ/2a⇒x1=9+7/2=8; x2=9-7/2=1
a>0;Δ>0⇒S=(1,8)
3x²-2x²-7x-2x+6+2<0
x²-9x+8<0
Δ=81-4*1*8=81-32=49
Δ=+7,-7
x1,2=-b+√Δ/2a⇒x1=9+7/2=8; x2=9-7/2=1
a>0;Δ>0⇒S=(1,8)
a)3x patrat -7x+6<2(xpatrat+x-1)=> 3x patrat-7x+6<2x patrat +2x-1 => 3xpatrat-2x patrat-7x-2x<-1-6 => xpatrat -5x+7<0 delta. =25-28=-3