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Rezolvati  ecuatia 2[tex] x^{2} [/tex]-5x+2=0

Răspuns :

XAndiask
Δ=b²-4ac
Δ=(-5)²-4*2*2
Δ=25-16
Δ=9
x1=(-b+√Δ)/2a = (5+3)/4=8/4=2
x2=(-b-√Δ)/2a= (5-3)/4=2/4=1/2
S={1/2, 2}
Alexandra9loveask
2-5x+2=0
2-5x=2+0
2-5x=2
5x=2+2
5x=4
x=4:5
x=0,8
 Sper ca e bine!