Calculati:
a)5/3√3+1/√12
b)7/√18-11/√50
c)3/√20-7/√45-1/√15+5/√32



Răspuns :

a) [tex] \frac{5}{3 \sqrt{3} } + \frac{1}{2 \sqrt{3} } = \frac{5 \sqrt{3} }{9} + \frac{ \sqrt{3} }{6} = \frac{10 \sqrt{3}+3 \sqrt{3} }{18} = \frac{13 \sqrt{3} }{18} [/tex]
b)[tex] \frac{7}{3 \sqrt{2} } - \frac{11}{5 \sqrt{2} } = \frac{7 \sqrt{2} }{6} - \frac{11 \sqrt{2} }{10} = \frac{35 \sqrt{2}-33 \sqrt{2} }{30} = \frac{ \sqrt{2} }{15} [/tex]
c)[tex] \frac{3}{2 \sqrt{5} } - \frac{7}{3 \sqrt{5} } - \frac{1}{ \sqrt{15} } + \frac{5}{4 \sqrt{2} } = \frac{3 \sqrt{5} }{10} - \frac{7 \sqrt{5} }{15} - \frac{ \sqrt{15} }{15} + \frac{5 \sqrt{2} }{8} [/tex]=..... asta poti sa calculezi si tu