[tex]B+C=180 ^{0} \\ B+35^{0}=180 ^{0} \\ B=145 ^{0}[/tex]
[tex](- \frac{1}{3}) ^{3}:(- \frac{1}{3})^{2}+ \frac{12}{75}: \frac{3}{25} = \\ = (- \frac{1}{27}):\frac{1}{9}+ \frac{12}{75}* \frac{25}{3}= \\ = (- \frac{1}{27})* \frac{9}{1}+ \frac{4}{3} = \\ =- \frac{1}{3}+ \frac{4}{3} = \\ = \frac{4-1}{3}= \\ = \frac{2}{3} [/tex]
