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2.Stiind ca a supra 11 = b supra 3 , calculati 7a-2b/3a+5b

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Andyilyeask
[tex] \frac{a}{11}= \frac{b}{3}=k \\ a=11k;b=3k \\ \frac{7a-2b}{3a+5b}= \frac{7*11k-2*3k}{3*11k+5*3k}=\frac{77k-6k}{33k+15k}= \frac{71k}{48k} = \frac{71}{48} [/tex]

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