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Se amesteca 2 kg solutie de sare 35% cu 5 kg solutie de sare 15% si 3 kg de apa .Aflati concentratia solutiei finale

Răspuns :

Alexutzuu10ask
[tex]md_{1} [/tex] = [tex] \frac{ms*c}{100} = \frac{2*35}{100} = \frac{70}{100} = 0,7[/tex] kg sare

[tex]md_{2} [/tex] = [tex] \frac{5*15}{100} = \frac{75}{100} = 0,75 [/tex] kg sare

[tex]ms_{final} = 2 + 5 + 3 = 10 kg [/tex]

[tex]md_{final} = 0,7 + 0,75 = 1,45[/tex] kg sare

[tex] c_{finala} = \frac{ md_{final}}{ms_{final}} * 100 = \frac{1,45*100}{10}[/tex] = 14,5%
AndraDobreask
ms1=2kg=2000g
C1=35%
md1=[tex] \frac{C1*ms1}{100} [/tex]= [tex] \frac{35*2000}{100} [/tex]= 700 g
ms2=5 kg=5000g
C2=15%
md2= [tex] \frac{C2*ms2}{100}= \frac{15*5000}{100} [/tex]= 750g
mH2O= 3kg= 3000g
mdfinal= md1+md2= 700+750=1450g
msfinal= ms1+ms2+mH2O= 2000+5000+3000= 10000g
Cfinal= [tex] \frac{mdfinal}{msfinal}*100 [/tex]= [tex] \frac{1450}{10000}*100 [/tex]= 14,5 %

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