SKAWPask
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3√3=a^2 √3/4

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Miky93ask
a²= 4*3√3/√3

a²=4*3
a²=12

√a²=√12
|a|=2√3  ⇒a∈{-2√3; 2√3}
[tex]3\sqrt3=\dfrac{a^2\sqrt3}{4}\Rightarrow a^2=\dfrac{4\cdot3\sqrt3}{\sqrt3}\Rightarrow a^2=12\Rightarrow a_{1;2}=\pm\sqrt{12}=\pm2\sqrt3[/tex]

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